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The square of a positive number is 2000% greater than the number itself, then the square of that number is :

11762
21635
3441
4139

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the positive number be x . \\ According to the question, \\ x \times x = x + \frac{(x \times 2000)}{100} \\ x^{2} = x + 20 x \\ x^{2} - 21 x = 0 \\ Either, \\ x = 0, o r \\ x = 21 \\ 21 is the possible value . \\ Then square of 21 is 441. \end{aligned}

$\eqalign{ & {\text{Let the positive number be x}}. \cr & {\text{According}}\,{\text{to}}\,{\text{the}}\,{\text{question}}, \cr & x \times x = x + \frac{{\left( {x \times 2000} \right)}}{{100}} \cr & {x^2} = x + 20x \cr & {x^2} - 21x = 0 \cr & {\text{Either}}, \cr & x = 0,\,\,or \cr & x = 21 \cr & {\text{21}}\,{\text{is}}\,{\text{the}}\,{\text{possible}}\,{\text{value}}{\text{.}} \cr & {\text{Then}}\,{\text{square}}\,{\text{of}}\,21\,{\text{is}}\,441. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let the positive number be x . \\ According to the question, \\ x \times x = x + \frac{(x \times 2000)}{100} \\ x^{2} = x + 20 x \\ x^{2} - 21 x = 0 \\ Either, \\ x = 0, o r \\ x = 21 \\ 21 is the possible value . \\ Then square of 21 is 441. \end{aligned}

$\eqalign{ & {\text{Let the positive number be x}}. \cr & {\text{According}}\,{\text{to}}\,{\text{the}}\,{\text{question}}, \cr & x \times x = x + \frac{{\left( {x \times 2000} \right)}}{{100}} \cr & {x^2} = x + 20x \cr & {x^2} - 21x = 0 \cr & {\text{Either}}, \cr & x = 0,\,\,or \cr & x = 21 \cr & {\text{21}}\,{\text{is}}\,{\text{the}}\,{\text{possible}}\,{\text{value}}{\text{.}} \cr & {\text{Then}}\,{\text{square}}\,{\text{of}}\,21\,{\text{is}}\,441. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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