What is the percentage change in the result when we add 50 to a certain number x, instead of subtracting 50 from the same number x?

150%
275%
3100%
4Can't be determined

Answer:- 1

Explanation:-

Solution:

\begin{aligned} If we take different values of x then, \\ Let x = 150 \\ then % error = \frac{[\frac{(200 - 100)}{100}]}{100} = 100 % \\ Again i f x = 100 \\ then % error = \frac{[(150 - 50) \times 100]}{100} = 200 % \\ If we take different value of x, \\ we get different answer so we can't determine it . \end{aligned}

$\eqalign{ & {\text{If we take different values of }}x{\text{ then}}, \cr & {\text{Let}}\,x = 150 \cr & {\text{then}}\,\% \,{\text{error}} = \frac{{\left[ {\frac{{\left( {200 - 100} \right)}}{{100}}} \right]}}{{100}} = 100\% \cr & {\text{Again}}\,if\,x = 100 \cr & {\text{then}}\,\% \,{\text{error}} = \frac{{\left[ {\left( {150 - 50} \right) \times 100} \right]}}{{100}} = 200\% \cr & {\text{If we take different value of }}x, \cr & {\text{we get different answer so we can't determine it}}. \cr}$