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The population of a village is 5000 and it increases at the rate of 2% every year. After 2 years, the population will be:

15116
25202
35200
45204

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Population after two years, \\ = 5000 \times {[1 + (\frac{2}{100})]}^{2} \\ = 5202 \\ Alternatively, \\ 5000 == 2 % ↑=\Rightarrow 5100 == 2 % ↑=\Rightarrow 5204 \end{aligned}

$\eqalign{ & {\text{Population after two years}}, \cr & = 5000 \times {\left[ {1 + \left( {\frac{2}{{100}}} \right)} \right]^2} \cr & = 5202 \cr & {\text{Alternatively}}, \cr & 5000 = = 2\% \uparrow = \Rightarrow 5100 = = 2\% \uparrow = \Rightarrow 5204 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Population after two years, \\ = 5000 \times {[1 + (\frac{2}{100})]}^{2} \\ = 5202 \\ Alternatively, \\ 5000 == 2 % ↑=\Rightarrow 5100 == 2 % ↑=\Rightarrow 5204 \end{aligned}

$\eqalign{ & {\text{Population after two years}}, \cr & = 5000 \times {\left[ {1 + \left( {\frac{2}{{100}}} \right)} \right]^2} \cr & = 5202 \cr & {\text{Alternatively}}, \cr & 5000 = = 2\% \uparrow = \Rightarrow 5100 = = 2\% \uparrow = \Rightarrow 5204 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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