A spider climbed 125/2% of the height of the pole in one hour and in the next hour it covered 25/2% of remaining height. If pole's height is 192 m, then distance climbed in second hour is:

Explanation:-

$$\eqalign{ & {\text{Height}}\,{\text{of}}\,{\text{the}}\,{\text{Pole}} = 192\,m. \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{first}}\,{\text{hour}}, \cr & = \frac{{125}}{2}\% \,of\,192 \cr & = \frac{{\left( {125 \times 192} \right)}}{{\left( {2 \times 100} \right)}} \cr & = 120\,m \cr & {\text{Remaining}}\,Pole = 192 - 120 = 72\,m \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{second}}\,{\text{hour}}, \cr & = \frac{{25}}{2}\% \,{\text{of}}\,{\text{remaining}}\,{\text{height}} \cr & = \frac{{\left( {25 \times 72} \right)}}{{\left( {2 \times 100} \right)}} \cr & = 9\,m \cr}$$