Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

139, 30
241, 32
342, 33
443, 34

Answer:- 1

Explanation:-

Solution:

Let their marks be (x + 9) and x.
Then,

\begin{aligned} x + 9 = \frac{56}{100} (x + 9 + x) \\ \Rightarrow 25 (x + 9) = 14 (2 x + 9) \\ \Rightarrow 3 x = 99 \\ \Rightarrow x = 33 \end{aligned}

$\eqalign{ & x + 9 = \frac{{56}}{{100}}\left( {x + 9 + x} \right) \cr & \Rightarrow 25\left( {x + 9} \right) = 14\left( {2x + 9} \right) \cr & \Rightarrow 3x = 99 \cr & \Rightarrow x = 33 \cr}$ So, their marks are 42 and 33.

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So, their marks are 42 and 33. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let their marks be (x + 9) and x.
Then,