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Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

1Rs. 200
2Rs. 250
3Rs. 300
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the sum paid to y per week be R s . z . \\ Then, z + 120 % o f z = 550. \\ \Rightarrow z + \frac{120}{100} z = 550 \\ \Rightarrow \frac{11}{5} z = 550 \\ \Rightarrow z = (\frac{550 \times 5}{11}) = 250. \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{sum}}\,{\text{paid}}\,{\text{to}}\,{\text{y}}\,{\text{per}}\,{\text{week}}\,{\text{be}}\,Rs.\,z. \cr & {\text{Then}},\,z + 120\% \,of\,z = 550. \cr & \Rightarrow z + \frac{{120}}{{100}}z = 550 \cr & \Rightarrow \frac{{11}}{5}z = 550 \cr & \Rightarrow z = \left( {\frac{{550 \times 5}}{{11}}} \right) = 250. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let the sum paid to y per week be R s . z . \\ Then, z + 120 % o f z = 550. \\ \Rightarrow z + \frac{120}{100} z = 550 \\ \Rightarrow \frac{11}{5} z = 550 \\ \Rightarrow z = (\frac{550 \times 5}{11}) = 250. \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{sum}}\,{\text{paid}}\,{\text{to}}\,{\text{y}}\,{\text{per}}\,{\text{week}}\,{\text{be}}\,Rs.\,z. \cr & {\text{Then}},\,z + 120\% \,of\,z = 550. \cr & \Rightarrow z + \frac{{120}}{{100}}z = 550 \cr & \Rightarrow \frac{{11}}{5}z = 550 \cr & \Rightarrow z = \left( {\frac{{550 \times 5}}{{11}}} \right) = 250. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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