x2−2+1x2x2−2+1x2{x^2} - 2 + \frac{1}{{{x^2}}} is?" /> x2−2+1x2x2−2+1x2{x^2} - 2 + \frac{1}{{{x^2}}} is?" /> x2−2+1x2x2−2+1x2{x^2} - 2 + \frac{1}{{{x^2}}} is?" />

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If x = y, then the value of the expression $x^{2} - 2 + \frac{1}{x^{2}}$ ${x^2} - 2 + \frac{1}{{{x^2}}}$ is?

1 $\frac{576}{25}$ $\frac{{576}}{{25}}$
2 $\frac{24}{25}$ $\frac{{24}}{{25}}$
3 $\frac{24}{5}$ $\frac{{24}}{5}$
4 $\frac{625}{24}$ $\frac{{625}}{{24}}$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to the question, \\ If x = 5 \\ ∴ x^{2} - 2 + \frac{1}{x^{2}} \\ = {(x - \frac{1}{x})}^{2} \\ = {(5 - \frac{1}{5})}^{2} \\ = {(\frac{24}{5})}^{2} \\ = \frac{576}{25} \end{aligned}

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is?", "text": "If x = y, then the value of the expression

x^{2} - 2 + \frac{1}{x^{2}}

${x^2} - 2 + \frac{1}{{{x^2}}}$ is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to the question, \\ If x = 5 \\ ∴ x^{2} - 2 + \frac{1}{x^{2}} \\ = {(x - \frac{1}{x})}^{2} \\ = {(5 - \frac{1}{5})}^{2} \\ = {(\frac{24}{5})}^{2} \\ = \frac{576}{25} \end{aligned}

$\eqalign{ & {\text{According to the question,}} \cr & {\text{If }}x = 5 \cr & \therefore {x^2} - 2 + \frac{1}{{{x^2}}} \cr & = {\left( {x - \frac{1}{x}} \right)^2} \cr & = {\left( {5 - \frac{1}{5}} \right)^2} \cr & = {\left( {\frac{{24}}{5}} \right)^2} \cr & = \frac{{576}}{{25}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: