(x+y+z)2x2+y2+z2(x+y+z)2x2+y2+z2\frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}} is?" /> (x+y+z)2x2+y2+z2(x+y+z)2x2+y2+z2\frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}} is?" /> (x+y+z)2x2+y2+z2(x+y+z)2x2+y2+z2\frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}} is?" />

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If x = y = z, then $\frac{{(x + y + z)}^{2}}{x^{2} + y^{2} + z^{2}}$ $\frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}}$ is?

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{{(x + y + z)}^{2}}{x^{2} + y^{2} + z^{2}} \\ Assume x = y = z = 1 \\ \Leftrightarrow \frac{{(1 + 1 + 1)}^{2}}{1 + 1 + 1} \\ \Leftrightarrow \frac{9}{3} \\ \Leftrightarrow 3 \end{aligned}

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is?", "text": "If x = y = z, then

\frac{{(x + y + z)}^{2}}{x^{2} + y^{2} + z^{2}}

$\frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}}$ is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{{(x + y + z)}^{2}}{x^{2} + y^{2} + z^{2}} \\ Assume x = y = z = 1 \\ \Leftrightarrow \frac{{(1 + 1 + 1)}^{2}}{1 + 1 + 1} \\ \Leftrightarrow \frac{9}{3} \\ \Leftrightarrow 3 \end{aligned}

$\eqalign{ & \frac{{{{\left( {x + y + z} \right)}^2}}}{{{x^2} + {y^2} + {z^2}}} \cr & {\text{Assume }}x = y = z = 1 \cr & \Leftrightarrow \frac{{{{\left( {1 + 1 + 1} \right)}^2}}}{{1 + 1 + 1}} \cr & \Leftrightarrow \frac{9}{3} \cr & \Leftrightarrow 3 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: