ab=256,ab=256,\frac{a}{b} = \frac{{25}}{6}{\text{,}} then the value of a2−b2a2+b2" role="presentation">a2−b2a2+b2a2−b2a2+b2\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} is?" /> ab=256,ab=256,\frac{a}{b} = \frac{{25}}{6}{\text{,}} then the value of a2−b2a2+b2" role="presentation">a2−b2a2+b2a2−b2a2+b2\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} is?" /> ab=256,ab=256,\frac{a}{b} = \frac{{25}}{6}{\text{,}} then the value of a2−b2a2+b2" role="presentation">a2−b2a2+b2a2−b2a2+b2\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} is?" />

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If $\frac{a}{b} = \frac{25}{6},$ $\frac{a}{b} = \frac{{25}}{6}{\text{,}}$ then the value of $\frac{a^{2} - b^{2}}{a^{2} + b^{2}}$ $\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}}$ is?

1 $\frac{589}{651}$ $\frac{{589}}{{651}}$
2 $\frac{589}{661}$ $\frac{{589}}{{661}}$
3 $\frac{661}{589}$ $\frac{{661}}{{589}}$
4 $\frac{625}{36}$ $\frac{{625}}{{36}}$

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{a}{b} = \frac{25}{6} \\ \frac{a^{2}}{b^{2}} = \frac{25^{2}}{6^{2}} \\ \Rightarrow \frac{a^{2} - b^{2}}{a^{2} + b^{2}} \\ \Rightarrow \frac{25^{2} - 6^{2}}{25^{2} + 6^{2}} \\ \Rightarrow \frac{625 - 36}{625 + 36} \\ \Rightarrow \frac{589}{661} \end{aligned}

$\eqalign{ & \frac{a}{b} = \frac{{25}}{6} \cr & \frac{{{a^2}}}{{{b^2}}} = \frac{{{{25}^2}}}{{{6^2}}} \cr & \Rightarrow \frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} \cr & \Rightarrow \frac{{{{25}^2} - {6^2}}}{{{{25}^2} + {6^2}}} \cr & \Rightarrow \frac{{625 - 36}}{{625 + 36}} \cr & \Rightarrow \frac{{589}}{{661}} \cr}$

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then the value of

\frac{a^{2} - b^{2}}{a^{2} + b^{2}}

$\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}}$ is?", "text": "If

\frac{a}{b} = \frac{25}{6},

$\frac{a}{b} = \frac{{25}}{6}{\text{,}}$ then the value of

\frac{a^{2} - b^{2}}{a^{2} + b^{2}}

$\frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}}$ is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{a}{b} = \frac{25}{6} \\ \frac{a^{2}}{b^{2}} = \frac{25^{2}}{6^{2}} \\ \Rightarrow \frac{a^{2} - b^{2}}{a^{2} + b^{2}} \\ \Rightarrow \frac{25^{2} - 6^{2}}{25^{2} + 6^{2}} \\ \Rightarrow \frac{625 - 36}{625 + 36} \\ \Rightarrow \frac{589}{661} \end{aligned}

$\eqalign{ & \frac{a}{b} = \frac{{25}}{6} \cr & \frac{{{a^2}}}{{{b^2}}} = \frac{{{{25}^2}}}{{{6^2}}} \cr & \Rightarrow \frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} \cr & \Rightarrow \frac{{{{25}^2} - {6^2}}}{{{{25}^2} + {6^2}}} \cr & \Rightarrow \frac{{625 - 36}}{{625 + 36}} \cr & \Rightarrow \frac{{589}}{{661}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{a}{b} = \frac{25}{6} \\ \frac{a^{2}}{b^{2}} = \frac{25^{2}}{6^{2}} \\ \Rightarrow \frac{a^{2} - b^{2}}{a^{2} + b^{2}} \\ \Rightarrow \frac{25^{2} - 6^{2}}{25^{2} + 6^{2}} \\ \Rightarrow \frac{625 - 36}{625 + 36} \\ \Rightarrow \frac{589}{661} \end{aligned}

$\eqalign{ & \frac{a}{b} = \frac{{25}}{6} \cr & \frac{{{a^2}}}{{{b^2}}} = \frac{{{{25}^2}}}{{{6^2}}} \cr & \Rightarrow \frac{{{a^2} - {b^2}}}{{{a^2} + {b^2}}} \cr & \Rightarrow \frac{{{{25}^2} - {6^2}}}{{{{25}^2} + {6^2}}} \cr & \Rightarrow \frac{{625 - 36}}{{625 + 36}} \cr & \Rightarrow \frac{{589}}{{661}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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