2x+14x=1,2x+14x=1,2x + \frac{1}{{4x}} = 1{\text{,}} then the value of x2+164x2" role="presentation">x2+164x2x2+164x2{x^2} + \frac{1}{{64{x^2}}} is?" /> 2x+14x=1,2x+14x=1,2x + \frac{1}{{4x}} = 1{\text{,}} then the value of x2+164x2" role="presentation">x2+164x2x2+164x2{x^2} + \frac{1}{{64{x^2}}} is?" /> 2x+14x=1,2x+14x=1,2x + \frac{1}{{4x}} = 1{\text{,}} then the value of x2+164x2" role="presentation">x2+164x2x2+164x2{x^2} + \frac{1}{{64{x^2}}} is?" />

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If $2 x + \frac{1}{4 x} = 1,$ $2x + \frac{1}{{4x}} = 1{\text{,}}$ then the value of $x^{2} + \frac{1}{64 x^{2}}$ ${x^2} + \frac{1}{{64{x^2}}}$ is?

10
21
3 $\frac{1}{4}$ $\frac{1}{4}$
42

Answer:- 1

Explanation:-

Solution:

\begin{aligned} 2 x + \frac{1}{4 x} = 1 \\ Dividing by 2 both side \\ \Rightarrow x + \frac{1}{8 x} = \frac{1}{2} \\ Squaring both side \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + 2 \times x \times \frac{1}{8 x} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + \frac{1}{4} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = \frac{1}{4} - \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = 0 \end{aligned}

$\eqalign{ & 2x + \frac{1}{{4x}} = 1 \cr & {\text{Dividing by 2 both side}} \cr & \Rightarrow x + \frac{1}{{8x}} = \frac{1}{2} \cr & {\text{Squaring both side }} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + 2 \times x \times \frac{1}{{8x}} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + \frac{1}{4} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = \frac{1}{4} - \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = 0 \cr}$

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then the value of

x^{2} + \frac{1}{64 x^{2}}

${x^2} + \frac{1}{{64{x^2}}}$ is?", "text": "If

2 x + \frac{1}{4 x} = 1,

$2x + \frac{1}{{4x}} = 1{\text{,}}$ then the value of

x^{2} + \frac{1}{64 x^{2}}

${x^2} + \frac{1}{{64{x^2}}}$ is?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 2 x + \frac{1}{4 x} = 1 \\ Dividing by 2 both side \\ \Rightarrow x + \frac{1}{8 x} = \frac{1}{2} \\ Squaring both side \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + 2 \times x \times \frac{1}{8 x} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + \frac{1}{4} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = \frac{1}{4} - \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = 0 \end{aligned}

$\eqalign{ & 2x + \frac{1}{{4x}} = 1 \cr & {\text{Dividing by 2 both side}} \cr & \Rightarrow x + \frac{1}{{8x}} = \frac{1}{2} \cr & {\text{Squaring both side }} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + 2 \times x \times \frac{1}{{8x}} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + \frac{1}{4} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = \frac{1}{4} - \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = 0 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 2 x + \frac{1}{4 x} = 1 \\ Dividing by 2 both side \\ \Rightarrow x + \frac{1}{8 x} = \frac{1}{2} \\ Squaring both side \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + 2 \times x \times \frac{1}{8 x} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} + \frac{1}{4} = \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = \frac{1}{4} - \frac{1}{4} \\ \Rightarrow x^{2} + \frac{1}{64 x^{2}} = 0 \end{aligned}

$\eqalign{ & 2x + \frac{1}{{4x}} = 1 \cr & {\text{Dividing by 2 both side}} \cr & \Rightarrow x + \frac{1}{{8x}} = \frac{1}{2} \cr & {\text{Squaring both side }} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + 2 \times x \times \frac{1}{{8x}} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} + \frac{1}{4} = \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = \frac{1}{4} - \frac{1}{4} \cr & \Rightarrow {x^2} + \frac{1}{{64{x^2}}} = 0 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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