India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

If (x - y)² + (y - 2)² + (z - 9)² = 0, then the value of (x + y - z) is?

116
2-1
3-2
412

Answer:- 1

Explanation:-

Solution:

\begin{aligned} {(x - 5)}^{2} + {(y - 2)}^{2} + {(z - 9)}^{2} = 0 \\ It is possible only when \\ x - 5 = 0 \\ x = 5 \\ y - 2 = 0 \\ y = 2 \\ z - 9 = 0 \\ z = 9 \\ ∴ x + y - z \\ = 5 + 2 - 9 \\ = 7 - 9 \\ = - 2 \end{aligned}

$\eqalign{ & {\left( {x - 5} \right)^2} + {\left( {y - 2} \right)^2} + {\left( {z - 9} \right)^2} = 0 \cr & {\text{It is possible only when }} \cr & x - 5 = 0 \cr & x = 5 \cr & y - 2 = 0 \cr & y = 2 \cr & z - 9 = 0 \cr & z = 9 \cr & \therefore x + y - z \cr & = 5 + 2 - 9 \cr & = 7 - 9 \cr & = - 2 \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} {(x - 5)}^{2} + {(y - 2)}^{2} + {(z - 9)}^{2} = 0 \\ It is possible only when \\ x - 5 = 0 \\ x = 5 \\ y - 2 = 0 \\ y = 2 \\ z - 9 = 0 \\ z = 9 \\ ∴ x + y - z \\ = 5 + 2 - 9 \\ = 7 - 9 \\ = - 2 \end{aligned}

$\eqalign{ & {\left( {x - 5} \right)^2} + {\left( {y - 2} \right)^2} + {\left( {z - 9} \right)^2} = 0 \cr & {\text{It is possible only when }} \cr & x - 5 = 0 \cr & x = 5 \cr & y - 2 = 0 \cr & y = 2 \cr & z - 9 = 0 \cr & z = 9 \cr & \therefore x + y - z \cr & = 5 + 2 - 9 \cr & = 7 - 9 \cr & = - 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book