If x = 222, y = 223, z = 225, then the value of x3 + y3 + z3 is?

  • 14590
  • 24690
  • 34950
  • 44960
Answer:- 1
Explanation:-

Solution:
x3+y3+z33xyz=12(x+y+z)[(xy)2+(yz)2+(zx)2]=12(222+223+225)[(222223)2+(223225)2+(225223)2]=12(670)(1+4+9)=12×670×14=4690

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
x3+y3+z33xyz=12(x+y+z)[(xy)2+(yz)2+(zx)2]=12(222+223+225)[(222223)2+(223225)2+(225223)2]=12(670)(1+4+9)=12×670×14=4690
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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