a3+1a3=2,a3+1a3=2,{a^3} + \frac{1}{{{a^3}}} = 2{\text{,}} then the value of a2+1a" role="presentation">a2+1aa2+1a\frac{{{a^2} + 1}}{a} is (a positive number) ?" /> a3+1a3=2,a3+1a3=2,{a^3} + \frac{1}{{{a^3}}} = 2{\text{,}} then the value of a2+1a" role="presentation">a2+1aa2+1a\frac{{{a^2} + 1}}{a} is (a positive number) ?" /> a3+1a3=2,a3+1a3=2,{a^3} + \frac{1}{{{a^3}}} = 2{\text{,}} then the value of a2+1a" role="presentation">a2+1aa2+1a\frac{{{a^2} + 1}}{a} is (a positive number) ?" />

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If $a^{3} + \frac{1}{a^{3}} = 2,$ ${a^3} + \frac{1}{{{a^3}}} = 2{\text{,}}$ then the value of $\frac{a^{2} + 1}{a}$ $\frac{{{a^2} + 1}}{a}$ is (a positive number) ?

Answer:- 1

Explanation:-

Solution:

\begin{aligned} But a = 1 \\ a^{3} + \frac{1}{a^{3}} = 2 \\ \Rightarrow 1^{3} + \frac{1}{1^{3}} = 2 \\ \Rightarrow 2 = 2 (Satisfy) \\ So, \frac{a^{2} + 1}{a} \\ = \frac{1^{2} + 1}{1} \\ = 2 \end{aligned}

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then the value of

\frac{a^{2} + 1}{a}

$\frac{{{a^2} + 1}}{a}$ is (a positive number) ?", "text": "If

a^{3} + \frac{1}{a^{3}} = 2,

${a^3} + \frac{1}{{{a^3}}} = 2{\text{,}}$ then the value of

\frac{a^{2} + 1}{a}

$\frac{{{a^2} + 1}}{a}$ is (a positive number) ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} But a = 1 \\ a^{3} + \frac{1}{a^{3}} = 2 \\ \Rightarrow 1^{3} + \frac{1}{1^{3}} = 2 \\ \Rightarrow 2 = 2 (Satisfy) \\ So, \frac{a^{2} + 1}{a} \\ = \frac{1^{2} + 1}{1} \\ = 2 \end{aligned}

$\eqalign{ & {\text{But }}a = 1 \cr & {a^3} + \frac{1}{{{a^3}}} = 2 \cr & \Rightarrow {1^3} + \frac{1}{{{1^3}}} = 2 \cr & \Rightarrow 2 = 2{\text{ }}\left( {{\text{Satisfy}}} \right) \cr & {\text{So, }}\frac{{{a^2} + 1}}{a} \cr & = \frac{{{1^2} + 1}}{1} \cr & = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: