x+1x=2x+1x=2x + \frac{1}{x} = 2 then x2+1x2" role="presentation">x2+1x2x2+1x2{x^2} + \frac{1}{{{x^2}}} is equal to?" /> x+1x=2x+1x=2x + \frac{1}{x} = 2 then x2+1x2" role="presentation">x2+1x2x2+1x2{x^2} + \frac{1}{{{x^2}}} is equal to?" /> x+1x=2x+1x=2x + \frac{1}{x} = 2 then x2+1x2" role="presentation">x2+1x2x2+1x2{x^2} + \frac{1}{{{x^2}}} is equal to?" />

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If $x + \frac{1}{x} = 2$ $x + \frac{1}{x} = 2$ then $x^{2} + \frac{1}{x^{2}}$ ${x^2} + \frac{1}{{{x^2}}}$ is equal to?

Answer:- 1

Explanation:-

Solution:

\begin{aligned} x + \frac{1}{x} = 2 \\ But x = 1 \\ So, x^{2} + \frac{1}{x^{2}} = 1^{2} + \frac{1}{1^{2}} = 2 \end{aligned}

$\eqalign{ & x + \frac{1}{x} = 2{\text{ }} \cr & {\text{But }}x = 1 \cr & {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr}$

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then

x^{2} + \frac{1}{x^{2}}

${x^2} + \frac{1}{{{x^2}}}$ is equal to?", "text": "If

x + \frac{1}{x} = 2

$x + \frac{1}{x} = 2$ then

x^{2} + \frac{1}{x^{2}}

${x^2} + \frac{1}{{{x^2}}}$ is equal to?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} x + \frac{1}{x} = 2 \\ But x = 1 \\ So, x^{2} + \frac{1}{x^{2}} = 1^{2} + \frac{1}{1^{2}} = 2 \end{aligned}

$\eqalign{ & x + \frac{1}{x} = 2{\text{ }} \cr & {\text{But }}x = 1 \cr & {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} x + \frac{1}{x} = 2 \\ But x = 1 \\ So, x^{2} + \frac{1}{x^{2}} = 1^{2} + \frac{1}{1^{2}} = 2 \end{aligned}

$\eqalign{ & x + \frac{1}{x} = 2{\text{ }} \cr & {\text{But }}x = 1 \cr & {\text{So, }}{x^2} + \frac{1}{{{x^2}}} = {1^2} + \frac{1}{{{1^2}}} = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }