A complete factorisation of x4 + 64 is?

  • 1(x2 + 8)2
  • 2(x2 + 8)(x2 - 8)
  • 3(x2 - 4x + 8)(x2 - 4x - 8)
  • 4(x2 + 4x + 8)(x2 - 4x + 8)
Answer:- 1
Explanation:-

Solution:
(x4+64)=x4+82+2.x2.82.x2.8=(x2+8)2(16x2)=(x2+8)2(4x)2=(x2+8+4x)(x2+84x)=(x2+4x+8)(x24x+8)

Post your Comments

Your comments will be displayed only after manual approval.

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
(x4+64)=x4+82+2.x2.82.x2.8=(x2+8)2(16x2)=(x2+8)2(4x)2=(x2+8+4x)(x2+84x)=(x2+4x+8)(x24x+8)
", "dateCreated": "7/24/2019 10:09:12 AM" } }
Test
Classes
E-Book