If x2=y3=z4=2x−3y+5zk,If x2=y3=z4=2x−3y+5zk,{\text{If }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{{2x - 3y + 5z}}{k}{\text{,}} then the value of k is -" /> If x2=y3=z4=2x−3y+5zk,If x2=y3=z4=2x−3y+5zk,{\text{If }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{{2x - 3y + 5z}}{k}{\text{,}} then the value of k is -" /> If x2=y3=z4=2x−3y+5zk,If x2=y3=z4=2x−3y+5zk,{\text{If }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{{2x - 3y + 5z}}{k}{\text{,}} then the value of k is -" />

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$If \frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{2 x - 3 y + 5 z}{k},$ ${\text{If }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{{2x - 3y + 5z}}{k}{\text{,}}$ then the value of k is -

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let \frac{x}{2} = \frac{y}{3} = \frac{z}{4} = l . \\ Then, \\ = x = 2 l, y = 3 l, z = 4 l . \\ ∴ \frac{x}{2} = \frac{2 x - 3 y + 5 z}{k} \\ \Rightarrow \frac{2 l}{2} = \frac{2 \times 2 l - 3 \times 3 l + 5 \times 4 l}{k} \\ \Rightarrow k = 4 - 9 + 20 = 15. \end{aligned}

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then the value of k is -", "text": "

If \frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{2 x - 3 y + 5 z}{k},

${\text{If }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = \frac{{2x - 3y + 5z}}{k}{\text{,}}$ then the value of k is -", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let \frac{x}{2} = \frac{y}{3} = \frac{z}{4} = l . \\ Then, \\ = x = 2 l, y = 3 l, z = 4 l . \\ ∴ \frac{x}{2} = \frac{2 x - 3 y + 5 z}{k} \\ \Rightarrow \frac{2 l}{2} = \frac{2 \times 2 l - 3 \times 3 l + 5 \times 4 l}{k} \\ \Rightarrow k = 4 - 9 + 20 = 15. \end{aligned}

$\eqalign{ & {\text{Let }}\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = l. \cr & {\text{Then,}} \cr & = x = 2l,y = 3l,z = 4l. \cr & \therefore \frac{x}{2} = \frac{{2x - 3y + 5z}}{k} \cr & \Rightarrow \frac{{2l}}{2} = \frac{{2 \times 2l - 3 \times 3l + 5 \times 4l}}{k} \cr & \Rightarrow k = 4 - 9 + 20 = 15. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: