If a+bc=b+ca=c+ab=k,then k is equal to - If a+bc=b+ca=c+ab=k,then k is equal to - \eqalign{
& {\text{If }}\frac{{{\text{a}} + {\text{b}}}}{{\text{c}}} = \frac{{{\text{b}} + {\text{c}}}}{{\text{a}}} = \frac{{{\text{c}} + {\text{a}}}}{{\text{b}}} = {\text{k}}, \cr
& {\text{then k is equal to - }} \cr} " />
If a+bc=b+ca=c+ab=k,then k is equal to - If a+bc=b+ca=c+ab=k,then k is equal to - \eqalign{
& {\text{If }}\frac{{{\text{a}} + {\text{b}}}}{{\text{c}}} = \frac{{{\text{b}} + {\text{c}}}}{{\text{a}}} = \frac{{{\text{c}} + {\text{a}}}}{{\text{b}}} = {\text{k}}, \cr
& {\text{then k is equal to - }} \cr} " />
If a+bc=b+ca=c+ab=k,then k is equal to - If a+bc=b+ca=c+ab=k,then k is equal to -
If a+bc=b+ca=c+ab=k,then k is equal to - ",
"dateCreated": "7/24/2019 10:09:12 AM",
"author": {
"@type": "Person",
"name": "Nitin Sir"
},
"answerCount": "4",
"acceptedAnswer": {
"@type": "Answer",
"text": "
Solution:
a + b = ck,
b + c = ak,
c + a = bk
Adding, we get : 2(a + b + c) = ak + bk + ck
⇒ k(a + b + c) or k = 2
",
"dateCreated": "7/24/2019 10:09:12 AM",
"author": {
"@type": "Person",
"name": "Nitin Sir"
}
},
"suggestedAnswer": {
"@type": "Answer",
"text": "
Solution:
a + b = ck,
b + c = ak,
c + a = bk
Adding, we get : 2(a + b + c) = ak + bk + ck
⇒ k(a + b + c) or k = 2
",
"dateCreated": "7/24/2019 10:09:12 AM"
}
}
Post your Comments