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If a+bc=b+ca=c+ab=k,then k is equal to - If a+bc=b+ca=c+ab=k,then k is equal to - \eqalign{ & {\text{If }}\frac{{{\text{a}} + {\text{b}}}}{{\text{c}}} = \frac{{{\text{b}} + {\text{c}}}}{{\text{a}}} = \frac{{{\text{c}} + {\text{a}}}}{{\text{b}}} = {\text{k}}, \cr & {\text{then k is equal to - }} \cr} " /> If a+bc=b+ca=c+ab=k,then k is equal to - If a+bc=b+ca=c+ab=k,then k is equal to - \eqalign{ & {\text{If }}\frac{{{\text{a}} + {\text{b}}}}{{\text{c}}} = \frac{{{\text{b}} + {\text{c}}}}{{\text{a}}} = \frac{{{\text{c}} + {\text{a}}}}{{\text{b}}} = {\text{k}}, \cr & {\text{then k is equal to - }} \cr} " />

If a+bc=b+ca=c+ab=k,then k is equal to - 
If a+bc=b+ca=c+ab=k,then k is equal to - 
  • 10
  • 21
  • 32
  • 4a + b + c
Answer:- 1
Explanation:-

Solution:
a + b = ck,
b + c = ak,
c + a = bk
Adding, we get : 2(a + b + c) = ak + bk + ck
⇒ k(a + b + c) or k = 2

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", "text": "
If a+bc=b+ca=c+ab=k,then k is equal to - 
If a+bc=b+ca=c+ab=k,then k is equal to - ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
a + b = ck,
b + c = ak,
c + a = bk
Adding, we get : 2(a + b + c) = ak + bk + ck
⇒ k(a + b + c) or k = 2 ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
a + b = ck,
b + c = ak,
c + a = bk
Adding, we get : 2(a + b + c) = ak + bk + ck
⇒ k(a + b + c) or k = 2 ", "dateCreated": "7/24/2019 10:09:12 AM" } }
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