India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

Two numbers are respectively 20 percent and 50 percent more than a third number. These two numbers are in the ratio.

12 : 5
23 : 5
34 : 5
46 : 7

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the third number be x . \\ Then, \\ first number \\ = 120 % of x = \frac{120}{100} x = \frac{6 x}{5} . \\ And, second number \\ = 150 % of x = \frac{150}{100} x = \frac{3 x}{2} . \\ ∴ Required ratio \\ = \frac{6 x}{5} : \frac{3 x}{2} \\ = 12 : 15 \\ = 4 : 5. \end{aligned}

$\eqalign{ & {\text{Let the third number be }}x. \cr & {\text{Then,}} \cr & {\text{first number}} \cr & = 120\% {\text{ of }}x = \frac{{120}}{{100}}x = \frac{{6x}}{5}. \cr & {\text{And, second number}} \cr & = 150\% {\text{ of }}x = \frac{{150}}{{100}}x = \frac{{3x}}{2}. \cr & \therefore {\text{Required ratio}} \cr & = \frac{{6x}}{5}:\frac{{3x}}{2} \cr & = 12:15 \cr & = 4:5. \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let the third number be x . \\ Then, \\ first number \\ = 120 % of x = \frac{120}{100} x = \frac{6 x}{5} . \\ And, second number \\ = 150 % of x = \frac{150}{100} x = \frac{3 x}{2} . \\ ∴ Required ratio \\ = \frac{6 x}{5} : \frac{3 x}{2} \\ = 12 : 15 \\ = 4 : 5. \end{aligned}

$\eqalign{ & {\text{Let the third number be }}x. \cr & {\text{Then,}} \cr & {\text{first number}} \cr & = 120\% {\text{ of }}x = \frac{{120}}{{100}}x = \frac{{6x}}{5}. \cr & {\text{And, second number}} \cr & = 150\% {\text{ of }}x = \frac{{150}}{{100}}x = \frac{{3x}}{2}. \cr & \therefore {\text{Required ratio}} \cr & = \frac{{6x}}{5}:\frac{{3x}}{2} \cr & = 12:15 \cr & = 4:5. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book