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What is the ratio whose terms differ by 40 and the measure of which is ²/₇ ?

16 : 56
214 : 56
316 : 56
416 : 72

Answer:- 1

Explanation:-

Solution:

Let the terms of the ratio be x and x + 40.

\begin{aligned} Then, \\ = \frac{x}{x + 40} = \frac{2}{7} \\ \Rightarrow 7 x = 2 x + 80 \\ \Rightarrow 5 x = 80 \\ \Rightarrow x = 16. \\ ∴ Required ratio \\ = 16 : 56 \end{aligned}

$\eqalign{ & {\text{Then,}} \cr & = \frac{x}{{x + 40}} = \frac{2}{7} \cr & \Rightarrow 7x = 2x + 80 \cr & \Rightarrow 5x = 80 \cr & \Rightarrow x = 16. \cr & \therefore {\text{Required ratio}} \cr & = 16:56 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the terms of the ratio be x and x + 40.

\begin{aligned} Then, \\ = \frac{x}{x + 40} = \frac{2}{7} \\ \Rightarrow 7 x = 2 x + 80 \\ \Rightarrow 5 x = 80 \\ \Rightarrow x = 16. \\ ∴ Required ratio \\ = 16 : 56 \end{aligned}

$\eqalign{ & {\text{Then,}} \cr & = \frac{x}{{x + 40}} = \frac{2}{7} \cr & \Rightarrow 7x = 2x + 80 \cr & \Rightarrow 5x = 80 \cr & \Rightarrow x = 16. \cr & \therefore {\text{Required ratio}} \cr & = 16:56 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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