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Arrange the number a = ⁷/₁₀, b = ⁵/₈, c = ²/₃ in descending order = ?

1a > b > c
2a > c > b
3b > c > a
4c > b > a

Answer:- 1

Explanation:-

Solution:

\begin{aligned} a = \frac{7 \times 24}{10 \times 24} = \frac{168}{240} \\ b = \frac{5 \times 30}{8 \times 30} = \frac{150}{240} \\ c = \frac{2 \times 80}{3 \times 80} = \frac{160}{240} \\ The descending order \\ = a > c > b \end{aligned}

$\eqalign{ & a = \frac{{7 \times 24}}{{10 \times 24}} = \frac{{168}}{{240}} \cr & b = \frac{{5 \times 30}}{{8 \times 30}} = \frac{{150}}{{240}} \cr & c = \frac{{2 \times 80}}{{3 \times 80}} = \frac{{160}}{{240}} \cr & {\text{The descending order}} \cr & {\text{ = }}a > c > b \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} a = \frac{7 \times 24}{10 \times 24} = \frac{168}{240} \\ b = \frac{5 \times 30}{8 \times 30} = \frac{150}{240} \\ c = \frac{2 \times 80}{3 \times 80} = \frac{160}{240} \\ The descending order \\ = a > c > b \end{aligned}

$\eqalign{ & a = \frac{{7 \times 24}}{{10 \times 24}} = \frac{{168}}{{240}} \cr & b = \frac{{5 \times 30}}{{8 \times 30}} = \frac{{150}}{{240}} \cr & c = \frac{{2 \times 80}}{{3 \times 80}} = \frac{{160}}{{240}} \cr & {\text{The descending order}} \cr & {\text{ = }}a > c > b \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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