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Ratio of earnings of A and B is 8 : 9 respectively. If the earnings of A increase by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 16 : 9 respectively. What are A's earnings?

1Rs. 22000
2Rs. 28500
3Rs. 37000
4Cannot be determine

Answer:- 1

Explanation:-

Solution:

Let the earnings of A and B Rs. 8x and Rs. 9x respectively.
Then,

\begin{aligned} = \frac{150 % of 8 x}{75 % of 9 x} = \frac{16}{9} \\ \Rightarrow \frac{\frac{3}{2} \times 8 x}{\frac{3}{4} \times 9 x} = \frac{16}{9} \\ \Rightarrow \frac{16}{9} = \frac{16}{9} . \end{aligned}

$\eqalign{ & = \frac{{150\% {\text{ of }}8x}}{{75\% {\text{ of }}9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{\frac{3}{2} \times 8x}}{{\frac{3}{4} \times 9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{16}}{9} = \frac{{16}}{9}. \cr}$ Hence, A's earnings cannot be determined.

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Hence, A's earnings cannot be determined. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the earnings of A and B Rs. 8x and Rs. 9x respectively.
Then,

\begin{aligned} = \frac{150 % of 8 x}{75 % of 9 x} = \frac{16}{9} \\ \Rightarrow \frac{\frac{3}{2} \times 8 x}{\frac{3}{4} \times 9 x} = \frac{16}{9} \\ \Rightarrow \frac{16}{9} = \frac{16}{9} . \end{aligned}

$\eqalign{ & = \frac{{150\% {\text{ of }}8x}}{{75\% {\text{ of }}9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{\frac{3}{2} \times 8x}}{{\frac{3}{4} \times 9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{16}}{9} = \frac{{16}}{9}. \cr}$ Hence, A's earnings cannot be determined. ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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