# Last year, the ratio between the salaries of A and B was 3 : 4. But the ratios of their individual salaries between last year and this year were 4 : 5 and 2 : 3 respectively. If the sum of their present salaries is Rs. 4160, then how much is the salary of A now ?

• 1Rs. 1040
• 2Rs. 1600
• 3Rs. 2560
• 4Rs. 3120
Explanation:-

Solution:
let the salaries of A and B last year be Rs. 3x and Rs. 4x respectively.
Then,
$\begin{array}{rl}& \text{A's present salary}\\ & =\text{Rs}.\left(\frac{5}{4}×3x\right)\\ & =\text{Rs}\text{.}\left(\frac{15x}{4}\right).\\ & \text{B's present salary}\\ & =\text{Rs}\text{.}\left(\frac{3}{2}×4x\right)\\ & =\text{Rs}.6x.\\ & \therefore \frac{15x}{4}+6x=4160\\ & ⇒39x=4160×4\\ & ⇒x=\frac{4160×4}{39}.\\ & \text{So,}\\ & \text{A's present salary}\\ & =\text{Rs}\text{.}\left(\frac{15}{4}×\frac{4160×4}{39}\right)\\ & =\text{Rs}.1600.\end{array}$

$\begin{array}{rl}& \text{A's present salary}\\ & =\text{Rs}.\left(\frac{5}{4}×3x\right)\\ & =\text{Rs}\text{.}\left(\frac{15x}{4}\right).\\ & \text{B's present salary}\\ & =\text{Rs}\text{.}\left(\frac{3}{2}×4x\right)\\ & =\text{Rs}.6x.\\ & \therefore \frac{15x}{4}+6x=4160\\ & ⇒39x=4160×4\\ & ⇒x=\frac{4160×4}{39}.\\ & \text{So,}\\ & \text{A's present salary}\\ & =\text{Rs}\text{.}\left(\frac{15}{4}×\frac{4160×4}{39}\right)\\ & =\text{Rs}.1600.\end{array}$