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In a regiment the ratio between the number of officers to soldiers was 3 : 31 before. In a battle 6 officers and 22 soldiers were killed and the ratio become 1 : 13, the regiment before battle was = ?

131
238
321
428

Answer:- 1

Explanation:-

Solution:

Let the number of officers and soldiers = 3x, 31x
According to the question,

\begin{aligned} \Rightarrow \frac{3 x - 6}{31 x - 22} = \frac{1}{13} \\ \Rightarrow 39 x - 78 = 31 x - 22 \\ \Rightarrow 8 x = 56 \\ \Rightarrow x = 7 \end{aligned}

$\eqalign{ & \Rightarrow \frac{{3x - 6}}{{31x - 22}} = \frac{1}{{13}} \cr & \Rightarrow 39x - 78 = 31x - 22 \cr & \Rightarrow 8x = 56 \cr & \Rightarrow x = 7 \cr}$ So, number of officer before
= 3x = 3 × 7 = 21

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So, number of officer before
= 3x = 3 × 7 = 21 ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the number of officers and soldiers = 3x, 31x
According to the question,

\begin{aligned} \Rightarrow \frac{3 x - 6}{31 x - 22} = \frac{1}{13} \\ \Rightarrow 39 x - 78 = 31 x - 22 \\ \Rightarrow 8 x = 56 \\ \Rightarrow x = 7 \end{aligned}

$\eqalign{ & \Rightarrow \frac{{3x - 6}}{{31x - 22}} = \frac{1}{{13}} \cr & \Rightarrow 39x - 78 = 31x - 22 \cr & \Rightarrow 8x = 56 \cr & \Rightarrow x = 7 \cr}$ So, number of officer before
= 3x = 3 × 7 = 21 ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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