Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi's speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi's speed is:

Explanation:-

Ajay → (x+4) kmph.
A ________ 60 km _________ B
Ravi → x kmph.

Let the speed of Ravi be x kmph;
Hence, Ajay's speed = (x+4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 - 12 = 48 km.

According to question,

⁷²/_(x+4) = ⁴⁸/_x
Or, ³/_(x+4) = ²/_x
3x = 2x+8
Or, x = 8 kmph.