Two guns are fired from the same place at an interval of 6 minutes. A person approaching the place observes that 5 minutes 52 seconds have elapsed between the hearings of the sound of the two guns. If the velocity of the sound is 330 m/sec, the man was approaching that place at what speed (in km/h)?

Explanation:-

Difference of time = 6 min-5 mins. 52 secs = 8 secs.
Distance covered by man in 5 mins. 52 secs = distance covered by sound in 8 secs
= 330*8 = 2640 m.
Hence, speed of man
= ²⁶⁴⁰/₅ min. 52 secs;
= ^2640m/_{352 secs}
= 2640 * ¹⁸/_{352 * 5} kmph
= 27 kmph.