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In a 100m race, Kamal defeats Bimal by 5 seconds. If the speed of Kamal is 18 kmph, then the speed of Bimal is:

115.4 kmph
214.5 kmph
314.4 kmph
414 kmph

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Time taken by Kamal \\ = \frac{100}{(\frac{18 \times 5}{18})} \\ = 20 seconds \\ Hence, \\ Time taken by Bimal \\ 20 + 5 = 25 seconds \\ So, Bimal's speed \\ = \frac{100}{25} \\ = 4 \frac{m}{\sec} \\ = \frac{4 \times 18}{5} \\ = 14.4 kmph \end{aligned}

$\eqalign{ & {\text{Time taken by Kamal}} \cr & = \frac{{100}}{{\left( {\frac{{18 \times 5}}{{18}}} \right)}} \cr & = 20\,{\text{seconds}} \cr & {\text{Hence, }} \cr & {\text{Time taken by Bimal}} \cr & 20 + 5 = 25\,{\text{seconds}} \cr & {\text{So, Bimal's speed}} \cr & = \frac{{100}}{{25}} \cr & = 4\,\frac{m}{{\sec }} \cr & = \frac{{4 \times 18}}{5} \cr & = 14.4\,{\text{kmph}} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Time taken by Kamal \\ = \frac{100}{(\frac{18 \times 5}{18})} \\ = 20 seconds \\ Hence, \\ Time taken by Bimal \\ 20 + 5 = 25 seconds \\ So, Bimal's speed \\ = \frac{100}{25} \\ = 4 \frac{m}{\sec} \\ = \frac{4 \times 18}{5} \\ = 14.4 kmph \end{aligned}

$\eqalign{ & {\text{Time taken by Kamal}} \cr & = \frac{{100}}{{\left( {\frac{{18 \times 5}}{{18}}} \right)}} \cr & = 20\,{\text{seconds}} \cr & {\text{Hence, }} \cr & {\text{Time taken by Bimal}} \cr & 20 + 5 = 25\,{\text{seconds}} \cr & {\text{So, Bimal's speed}} \cr & = \frac{{100}}{{25}} \cr & = 4\,\frac{m}{{\sec }} \cr & = \frac{{4 \times 18}}{5} \cr & = 14.4\,{\text{kmph}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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