India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

When do the two hands of a clock of just after 3 pm make 30⁰ angel between them?

13:15:00
23:10:54
33:01:59
43:5:20

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{{(90 - 30)}^{0}}{5.5} \\ = \frac{(60 \times 2)}{11} \\ = 10 (\frac{10}{11}) \\ = 10 min 54 \sec \\ Thus, \\ Required time \\ = 3 : 10 : 54 \end{aligned}

$\eqalign{ & \frac{{{{\left( {90 - 30} \right)}^0}}}{{5.5}} \cr & = \frac{{\left( {60 \times 2} \right)}}{{11}} \cr & = 10\left( {\frac{{10}}{{11}}} \right) \cr & = 10\,\min \,54\,\sec \cr & {\text{Thus}}, \cr & {\text{Required}}\,{\text{time}} \cr & = 3:10:54 \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{{(90 - 30)}^{0}}{5.5} \\ = \frac{(60 \times 2)}{11} \\ = 10 (\frac{10}{11}) \\ = 10 min 54 \sec \\ Thus, \\ Required time \\ = 3 : 10 : 54 \end{aligned}

$\eqalign{ & \frac{{{{\left( {90 - 30} \right)}^0}}}{{5.5}} \cr & = \frac{{\left( {60 \times 2} \right)}}{{11}} \cr & = 10\left( {\frac{{10}}{{11}}} \right) \cr & = 10\,\min \,54\,\sec \cr & {\text{Thus}}, \cr & {\text{Required}}\,{\text{time}} \cr & = 3:10:54 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book