A is twice fast as B and B is thrice fast as C is. The journey covered by C in 3/2 hours will be covered by A is:

  • 115 minutes
  • 220 minutes
  • 330 minutes
  • 41 hour
Answer:- 1
Explanation:-

Solution:
Let speed of C = X
Then Speed of B = 3X
Then Speed of A = 6X
Ratio of the speed of A and C = 1:6
So, Greater the speed less time taken in journey.
C’s speed is 6 times less than A So A will take 1/6 of the total time taken C to covered same distance.
So, Time taken by A = 3/(2*6) = ¼ hours = 15 minutes.

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