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If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

150 km
256 km
370 km
480 km

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the actual distance travelled be x k m \\ Then, \frac{x}{10} = \frac{x + 20}{14} \\ \Rightarrow 14 x = 10 x + 200 \\ \Rightarrow 4 x = 200 \\ \Rightarrow x = 50 k m \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{actual}}\,{\text{distance}}\,{\text{travelled}}\,{\text{be}}\,x\,km \cr & {\text{Then}},\,\frac{x}{{10}} = \frac{{x + 20}}{{14}} \cr & \Rightarrow 14x = 10x + 200 \cr & \Rightarrow 4x = 200 \cr & \Rightarrow x = 50\,km \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let the actual distance travelled be x k m \\ Then, \frac{x}{10} = \frac{x + 20}{14} \\ \Rightarrow 14 x = 10 x + 200 \\ \Rightarrow 4 x = 200 \\ \Rightarrow x = 50 k m \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{actual}}\,{\text{distance}}\,{\text{travelled}}\,{\text{be}}\,x\,km \cr & {\text{Then}},\,\frac{x}{{10}} = \frac{{x + 20}}{{14}} \cr & \Rightarrow 14x = 10x + 200 \cr & \Rightarrow 4x = 200 \cr & \Rightarrow x = 50\,km \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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