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A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

135.55 km/hr
236 km/hr
371.11 km/hr
471 km/hr

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Total time taken \\ = (\frac{160}{64} + \frac{160}{80}) h r s \\ = \frac{9}{2} h r s \\ ∴ Average speed \\ = (320 \times \frac{2}{9}) km/hr \\ = 71.11 km/hr \end{aligned}

$\eqalign{ & {\text{Total}}\,{\text{time}}\,{\text{taken}} \cr & = \left( {\frac{{160}}{{64}} + \frac{{160}}{{80}}} \right)hrs \cr & = \frac{9}{2}\,hrs \cr & \therefore {\text{Average}}\,{\text{speed}} \cr & = \left( {320 \times \frac{2}{9}} \right)\,{\text{km/hr}} \cr & = 71.11\,{\text{km/hr}} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Total time taken \\ = (\frac{160}{64} + \frac{160}{80}) h r s \\ = \frac{9}{2} h r s \\ ∴ Average speed \\ = (320 \times \frac{2}{9}) km/hr \\ = 71.11 km/hr \end{aligned}

$\eqalign{ & {\text{Total}}\,{\text{time}}\,{\text{taken}} \cr & = \left( {\frac{{160}}{{64}} + \frac{{160}}{{80}}} \right)hrs \cr & = \frac{9}{2}\,hrs \cr & \therefore {\text{Average}}\,{\text{speed}} \cr & = \left( {320 \times \frac{2}{9}} \right)\,{\text{km/hr}} \cr & = 71.11\,{\text{km/hr}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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