710710\frac{7}{{10}} of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?" /> 710710\frac{7}{{10}} of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?" /> 710710\frac{7}{{10}} of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?" />

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A complete $\frac{7}{10}$ $\frac{7}{{10}}$ of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?

1 $10 \frac{1}{2} days$ $10\frac{1}{2}{\text{ days}}$
2 $12 \frac{2}{3} days$ $12\frac{2}{3}{\text{ days}}$
3 $13 \frac{1}{3} days$ $13\frac{1}{3}{\text{ days}}$
4 $8 \frac{1}{4} days$ $8\frac{1}{4}{\text{ days}}$

Answer:- 1

Explanation:-

Solution:

\frac{7}{10}

$\frac{7}{{10}}$ part of work has been completed by A in 15 days. Then,
Rest work = 1 -

\frac{7}{10}

$\frac{7}{{10}}$ =

\frac{3}{10}

$\frac{3}{{10}}$ part
Given, That

\frac{3}{10}

$\frac{3}{{10}}$ part of the work is completed by A and B together in 4 days. Means,
(A + B) completed the

\frac{3}{10}

$\frac{3}{{10}}$ of work in 4 days
So, (A + B)'s 1 day's work =

\frac{3}{10 \times 4}

$\frac{3}{{10 \times 4}}$ =

\frac{3}{40}

$\frac{3}{{40}}$
Hence,
(A + B) can complete the work in

\frac{40}{3}

$\frac{{40}}{3}$ =

13 \frac{1}{3}

$13\frac{1}{3}$ days

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of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?", "text": "A complete

\frac{7}{10}

$\frac{7}{{10}}$ of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\frac{7}{10}

$\frac{7}{{10}}$ part of work has been completed by A in 15 days. Then,
Rest work = 1 -

\frac{7}{10}

$\frac{7}{{10}}$ =

\frac{3}{10}

$\frac{3}{{10}}$ part
Given, That

\frac{3}{10}

$\frac{3}{{10}}$ part of the work is completed by A and B together in 4 days. Means,
(A + B) completed the

\frac{3}{10}

$\frac{3}{{10}}$ of work in 4 days
So, (A + B)'s 1 day's work =

\frac{3}{10 \times 4}

$\frac{3}{{10 \times 4}}$ =

\frac{3}{40}

$\frac{3}{{40}}$
Hence,
(A + B) can complete the work in

\frac{40}{3}

$\frac{{40}}{3}$ =

13 \frac{1}{3}

$13\frac{1}{3}$ days ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\frac{7}{10}

$\frac{7}{{10}}$ part of work has been completed by A in 15 days. Then,
Rest work = 1 -

\frac{7}{10}

$\frac{7}{{10}}$ =

\frac{3}{10}

$\frac{3}{{10}}$ part
Given, That

\frac{3}{10}

$\frac{3}{{10}}$ part of the work is completed by A and B together in 4 days. Means,
(A + B) completed the

\frac{3}{10}

$\frac{3}{{10}}$ of work in 4 days
So, (A + B)'s 1 day's work =

\frac{3}{10 \times 4}

$\frac{3}{{10 \times 4}}$ =

\frac{3}{40}

$\frac{3}{{40}}$
Hence,
(A + B) can complete the work in

\frac{40}{3}

$\frac{{40}}{3}$ =

13 \frac{1}{3}

$13\frac{1}{3}$ days ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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