X takes 4 days to complete one-third of a job. Y takes 3 days to complete one-sixth of the job and Z takes 5 days to complete half the job. If all of them work together for 3 days and X and Z quit, how long will it take for Y to complete the remaining work done.

16 days
28.1 days
35.1 days
47 days

Answer:- 1

Explanation:-

Solution:

X completes

\frac{1}{3}

$\frac{1}{3}$ rd in 4 days = 33.33% job in 4 days
X One day work = 8.33%
Y one day work = 5.55% [As he complete

\frac{1}{6}

$\frac{1}{6}$ job = 16.66% job in 3 days]
Z one day work = 10%
Work done in 3 days by X, Y and Z
= 25 + 16.66 + 30 = 71.66%
Remaining work will be done by Y in,

\frac{28.33}{5.55}

$\frac{{28.33}}{{5.55}}$ = 5.1 days

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rd in 4 days = 33.33% job in 4 days
X One day work = 8.33%
Y one day work = 5.55% [As he complete $\frac{1}{6}$ $\frac{1}{6}$ job = 16.66% job in 3 days]
Z one day work = 10%
Work done in 3 days by X, Y and Z
= 25 + 16.66 + 30 = 71.66%
Remaining work will be done by Y in,

\frac{28.33}{5.55}

$\frac{{28.33}}{{5.55}}$ = 5.1 days ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

X completes

\frac{1}{3}

$\frac{1}{3}$ rd in 4 days = 33.33% job in 4 days
X One day work = 8.33%
Y one day work = 5.55% [As he complete $\frac{1}{6}$ $\frac{1}{6}$ job = 16.66% job in 3 days]
Z one day work = 10%
Work done in 3 days by X, Y and Z
= 25 + 16.66 + 30 = 71.66%
Remaining work will be done by Y in,