Two men and women are entrusted with a task. The second man needs three hours more to cope up with the job than the second man and the woman would need working together. The first man, working alone, would need as much time as second man and the woman working together. The first man working alone, would spend eight hours less than the double period of the time second man would spend working alone. How much time would the two men and the women need to complete the task if they all asked together?

Explanation:-

Difference in times required by the first man (A) and second man (B) = 3 hours. Also, if t_a and t_b are the respective times, then
t_b - t_a = 3 . . . . . . . . . ..(1)
Also, B alone be take = (t_a + 3) h
According to the question,
2t_b - t_a = 8
2 × (t_a + 3) - t_a = 8 [Using equation (1)]
t_a = 2 hours.

Now B and woman together take 2 hours and A also take 2 hours, so time required will be half when all 3 work together. So in 1 hour work would be completed.