1341341\frac{3}{4} times as efficient as B. The same job can be done by A alone in :" /> 1341341\frac{3}{4} times as efficient as B. The same job can be done by A alone in :" /> 1341341\frac{3}{4} times as efficient as B. The same job can be done by A alone in :" />

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A and B can do a job together in 7 days. A is $1 \frac{3}{4}$ $1\frac{3}{4}$ times as efficient as B. The same job can be done by A alone in :

1 $9 \frac{1}{3}$ $9\frac{1}{3}$ days
211 days
3 $12 \frac{1}{4}$ $12\frac{1}{4}$ days
4 $16 \frac{1}{3}$ $16\frac{1}{3}$ days

Answer:- 1

Explanation:-

Solution:

\begin{aligned} (A's 1 day's work) : (B's 1 day's work) \\ = \frac{7}{4} : 1 = 7 : 4 \\ Let A's and B's 1 day's work be \\ 7 x and 4 x respectively \\ Then, 7 x + 4 x = \frac{1}{7} \\ \Rightarrow 11 x = \frac{1}{7} \\ \Rightarrow x = \frac{1}{77} \\ ∴ A's 1 day's work \\ = (\frac{1}{77} \times 7) = \frac{1}{11} \end{aligned}

$\eqalign{ & \left( {{\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right){\text{:}}\left( {{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right) \cr & = \frac{7}{4}:1 = 7:4 \cr & {\text{Let}}\,{\text{A's}}\,{\text{and}}\,{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}\,{\text{be}} \cr & 7x\,{\text{and}}\,4x\,{\text{respectively}} \cr & {\text{Then}},\,7x + 4x = \frac{1}{7} \cr & \Rightarrow 11x = \frac{1}{7} \cr & \Rightarrow x = \frac{1}{{77}} \cr & \therefore {\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}} \cr & = \left( {\frac{1}{{77}} \times {\text{7}}} \right) = \frac{1}{{11}} \cr}$

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times as efficient as B. The same job can be done by A alone in :", "text": "A and B can do a job together in 7 days. A is

1 \frac{3}{4}

$1\frac{3}{4}$ times as efficient as B. The same job can be done by A alone in :", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} (A's 1 day's work) : (B's 1 day's work) \\ = \frac{7}{4} : 1 = 7 : 4 \\ Let A's and B's 1 day's work be \\ 7 x and 4 x respectively \\ Then, 7 x + 4 x = \frac{1}{7} \\ \Rightarrow 11 x = \frac{1}{7} \\ \Rightarrow x = \frac{1}{77} \\ ∴ A's 1 day's work \\ = (\frac{1}{77} \times 7) = \frac{1}{11} \end{aligned}

$\eqalign{ & \left( {{\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right){\text{:}}\left( {{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right) \cr & = \frac{7}{4}:1 = 7:4 \cr & {\text{Let}}\,{\text{A's}}\,{\text{and}}\,{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}\,{\text{be}} \cr & 7x\,{\text{and}}\,4x\,{\text{respectively}} \cr & {\text{Then}},\,7x + 4x = \frac{1}{7} \cr & \Rightarrow 11x = \frac{1}{7} \cr & \Rightarrow x = \frac{1}{{77}} \cr & \therefore {\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}} \cr & = \left( {\frac{1}{{77}} \times {\text{7}}} \right) = \frac{1}{{11}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} (A's 1 day's work) : (B's 1 day's work) \\ = \frac{7}{4} : 1 = 7 : 4 \\ Let A's and B's 1 day's work be \\ 7 x and 4 x respectively \\ Then, 7 x + 4 x = \frac{1}{7} \\ \Rightarrow 11 x = \frac{1}{7} \\ \Rightarrow x = \frac{1}{77} \\ ∴ A's 1 day's work \\ = (\frac{1}{77} \times 7) = \frac{1}{11} \end{aligned}

$\eqalign{ & \left( {{\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right){\text{:}}\left( {{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}} \right) \cr & = \frac{7}{4}:1 = 7:4 \cr & {\text{Let}}\,{\text{A's}}\,{\text{and}}\,{\text{B's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}}\,{\text{be}} \cr & 7x\,{\text{and}}\,4x\,{\text{respectively}} \cr & {\text{Then}},\,7x + 4x = \frac{1}{7} \cr & \Rightarrow 11x = \frac{1}{7} \cr & \Rightarrow x = \frac{1}{{77}} \cr & \therefore {\text{A's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}} \cr & = \left( {\frac{1}{{77}} \times {\text{7}}} \right) = \frac{1}{{11}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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