In a cricket match if a batsman score 0,1,2,3,4,or 6 runs of a ball, then find the number or different sequences in which he can score exactly 30 runs of an over. Assume that an over consists of only 6 balls and there were no extra and no run outs.

Explanation:-

Case A: Five 6 and one 'zero', = 6!/5! =6.
Case B: Four 6 and one '2' and one '4', 6!/4! =30.
Case C: Three 6 and three '4' = 6!/(3!*3!)=20.
Case D: Four 6 and two '3' =6!/(4!*2!)=15.
Total number of different sequences = 71.