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A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

165 sec
289 sec
3100 sec
4150 sec

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Speed = (\frac{240}{24}) m/sec = 10 m/sec \\ ∴ Required time \\ = (\frac{240 + 650}{10}) sec . \\ = 89 s e c . \end{aligned}

$\eqalign{ & {\text{Speed}} = \left( {\frac{{240}}{{24}}} \right)\,{\text{m/sec}} = 10\,{\text{m/sec}} \cr & \therefore {\text{Required}}\,{\text{time}} \cr & {\text{ = }}\,\left( {\frac{{240 + 650}}{{10}}} \right)\,{\text{sec}}. \cr & = 89\,sec. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Speed = (\frac{240}{24}) m/sec = 10 m/sec \\ ∴ Required time \\ = (\frac{240 + 650}{10}) sec . \\ = 89 s e c . \end{aligned}

$\eqalign{ & {\text{Speed}} = \left( {\frac{{240}}{{24}}} \right)\,{\text{m/sec}} = 10\,{\text{m/sec}} \cr & \therefore {\text{Required}}\,{\text{time}} \cr & {\text{ = }}\,\left( {\frac{{240 + 650}}{{10}}} \right)\,{\text{sec}}. \cr & = 89\,sec. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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