Relative speed of the trains = (100+2002×60)m/sec = (52)m/secSpeed of train B = 120 kmph=(120×518)m/sec = (1003)m/secLet the speed of second train be x m/secThen, x−1003=52⇒x=(52+1003)=(2156)m/sec∴Speed of second train = (2156×185) kmph = 129 kmph
Relative speed of the trains = (100+2002×60)m/sec = (52)m/secSpeed of train B = 120 kmph=(120×518)m/sec = (1003)m/secLet the speed of second train be x m/secThen, x−1003=52⇒x=(52+1003)=(2156)m/sec∴Speed of second train = (2156×185) kmph = 129 kmph
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