When principal = Rs. S, rate of interest = 2r % p.a., then a person will get after 3 years at compound interest = ?

1Rs. ^6Sr/₁₀₀
2Rs. S(1 + ^r/₅₀)³
3Rs. S(1 + ^r/₁₀₀)³
4Rs. 3S(1 + ^r/₁₀₀)³

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to the question \\ Principal   =  Rs S \\ Rate % =  2r % p .a . \\ Time  =  3 years \\ ∴ A = P {(1 + \frac{r}{100})}^{T} \\ \Leftrightarrow A =  S {(1 + \frac{2r}{100})}^{3} \\ \Leftrightarrow A =  S {(1 + \frac{r}{50})}^{3} \end{aligned}

$\eqalign{ & {\text{According to the question}} \cr & {\text{Principal = Rs S}} \cr & {\text{Rate }}\% {\text{ = 2r}}\,\% {\text{ p}}{\text{.a}}{\text{.}} \cr & {\text{Time = 3 years}} \cr & \therefore {\text{A = P}}{\left( {1 + \frac{{\text{r}}}{{100}}} \right)^T} \cr & \Leftrightarrow {\text{A = S}}{\left( {1 + \frac{{{\text{2r}}}}{{100}}} \right)^3} \cr & \Leftrightarrow {\text{A = S}}{\left( {1 + \frac{{\text{r}}}{{50}}} \right)^3} \cr}$