# Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

• 112 years
• 213 years
• 314 years
• 415 years
Explanation:-

Solution:
Let son's age 10 years ago be x years.
Then, man's age 10 years ago = 7 years
Son's present age = (x + 10) years,
Man's present age = (7x + 10) years

Son's present age = (x + 10) years
= (4 + 10) years
= 14 years

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Son's present age = (x + 10) years
= (4 + 10) years
= 14 years ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Let son's age 10 years ago be x years.
Then, man's age 10 years ago = 7 years
Son's present age = (x + 10) years,
Man's present age = (7x + 10) years

Son's present age = (x + 10) years
= (4 + 10) years
= 14 years ", "dateCreated": "7/24/2019 10:09:12 AM" } }