The ratio of a man's age and his son's age is 7 : 3 and the product of their ages is 756. The ratio of their ages after 6 years will be ?

  • 15 : 2
  • 22 : 1
  • 311 : 7
  • 413 : 9
Answer:- 1
Explanation:-

Solution:
Let the man's age be 7x years ,
Then son's age = 3x years
7x×3x=75621x2=756x2=756x2=36x=6

The ratio of their ages after 6 years
 = (7x+6):(3x+6)=(7×6+6):(3×6+6)=48:24=2:1

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The ratio of their ages after 6 years
 = (7x+6):(3x+6)=(7×6+6):(3×6+6)=48:24=2:1
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Let the man's age be 7x years ,
Then son's age = 3x years
7x×3x=75621x2=756x2=756x2=36x=6

The ratio of their ages after 6 years
 = (7x+6):(3x+6)=(7×6+6):(3×6+6)=48:24=2:1
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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