At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?

15 min. past 7
25 ²/₁₁ min. past 7
35 ³/₁₁ min. past 7
45 ⁵/₁₁ min. past 7

Answer:- 1

Explanation:-

Solution:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
∴ Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
5 min. spaces are gained in

\begin{aligned} (\frac{60}{55} \times 5) min = 5 \frac{5}{11} min \\ ∴ Required time = 5 \frac{5}{11} min . p a s t 7 \end{aligned}

$\eqalign{ & \left( {\frac{{60}}{{55}} \times 5} \right)\,\min = 5\frac{5}{{11}}\,\min \cr & \therefore {\text{Required}}\,{\text{time}} = 5\frac{5}{{11}}\,\min .\,past\,7 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} (\frac{60}{55} \times 5) min = 5 \frac{5}{11} min \\ ∴ Required time = 5 \frac{5}{11} min . p a s t 7 \end{aligned}

$\eqalign{ & \left( {\frac{{60}}{{55}} \times 5} \right)\,\min = 5\frac{5}{{11}}\,\min \cr & \therefore {\text{Required}}\,{\text{time}} = 5\frac{5}{{11}}\,\min .\,past\,7 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }