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Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

13
210
317
420

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let the number be x \\ Then, x + 17 = \frac{60}{x} \\ \Rightarrow x^{2} + 17 x - 60 = 0 \\ \Rightarrow (x + 20) (x - 3) = 0 \\ \Rightarrow x = 3 \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{number}}\,{\text{be}}\,x \cr & {\text{Then}},\,x + 17 = \frac{{60}}{x} \cr & \Rightarrow {x^2} + 17x - 60 = 0 \cr & \Rightarrow (x + 20)(x - 3) = 0 \cr & \Rightarrow x = 3 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Let the number be x \\ Then, x + 17 = \frac{60}{x} \\ \Rightarrow x^{2} + 17 x - 60 = 0 \\ \Rightarrow (x + 20) (x - 3) = 0 \\ \Rightarrow x = 3 \end{aligned}

$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{number}}\,{\text{be}}\,x \cr & {\text{Then}},\,x + 17 = \frac{{60}}{x} \cr & \Rightarrow {x^2} + 17x - 60 = 0 \cr & \Rightarrow (x + 20)(x - 3) = 0 \cr & \Rightarrow x = 3 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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