The HCF of910,1225,1835 and 2140 is = ?The HCF of910,1225,1835 and 2140 is = ?\eqalign{ & {\text{The HCF of}} \cr & \frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}{\text{ and }}\frac{{21}}{{40}}{\text{ is = ?}} \cr} " /> The HCF of910,1225,1835 and 2140 is = ?The HCF of910,1225,1835 and 2140 is = ?\eqalign{ & {\text{The HCF of}} \cr & \frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}{\text{ and }}\frac{{21}}{{40}}{\text{ is = ?}} \cr} " /> The HCF of910,1225,1835 and 2140 is = ?The HCF of910,1225,1835 and 2140 is = ?\eqalign{ & {\text{The HCF of}} \cr & \frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}{\text{ and }}\frac{{21}}{{40}}{\text{ is = ?}} \cr} " />

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$\begin{aligned} The HCF of \\ \frac{9}{10}, \frac{12}{25}, \frac{18}{35} and \frac{21}{40} is = ? \end{aligned}$ $\eqalign{ & {\text{The HCF of}} \cr & \frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}{\text{ and }}\frac{{21}}{{40}}{\text{ is = ?}} \cr}$

1³/₅
2²⁵²/₅
3³/₁₄₀₀
4⁶³/₇₀₀

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Required HCF \\ = \frac{HCF of 9,12,18,21}{LCM of 10,25,35,40} \\ = \frac{3}{1400} \end{aligned}

$\eqalign{ & {\text{Required HCF }} \cr & {\text{ = }}\frac{{{\text{HCF of 9,12,18,21}}}}{{{\text{LCM of 10,25,35,40}}}} \cr & = \frac{3}{{1400}} \cr}$

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", "text": "

\begin{aligned} The HCF of \\ \frac{9}{10}, \frac{12}{25}, \frac{18}{35} and \frac{21}{40} is  =  ? \end{aligned}

$\eqalign{ & {\text{The HCF of}} \cr & \frac{9}{{10}}{\text{,}}\frac{{12}}{{25}}{\text{,}}\frac{{18}}{{35}}{\text{ and }}\frac{{21}}{{40}}{\text{ is = ?}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Required HCF \\ = \frac{HCF of 9,12,18,21}{LCM of 10,25,35,40} \\ = \frac{3}{1400} \end{aligned}

$\eqalign{ & {\text{Required HCF }} \cr & {\text{ = }}\frac{{{\text{HCF of 9,12,18,21}}}}{{{\text{LCM of 10,25,35,40}}}} \cr & = \frac{3}{{1400}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Required HCF \\ = \frac{HCF of 9,12,18,21}{LCM of 10,25,35,40} \\ = \frac{3}{1400} \end{aligned}

$\eqalign{ & {\text{Required HCF }} \cr & {\text{ = }}\frac{{{\text{HCF of 9,12,18,21}}}}{{{\text{LCM of 10,25,35,40}}}} \cr & = \frac{3}{{1400}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }