HCF of numbers = 7
Let the numbers are 7x and 7y
LCM = 7xy
7xy = 140 (given)
xy = 20
⇒ Possible co-prime factors of xy
= (1, 20), (4, 5)
⇒ Numbers are between 20 and 45
∴ Required number are = 4 × 7 = 28 and 5 × 7 = 35
⇒ Sum of numbers are = 28 + 35 = 63
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