The largest 4 - digit number exactly divisible by each of 12, 15, 18 and 27 is?

  • 19690
  • 29720
  • 39930
  • 49960
Answer:- 4
Explanation:-

Solution:
LCM of (12, 15, 18, 27)
⇒ 4 × 3 × 5 × 3 × 3 = 540
largest 4 - digits number = 9999 on dividing by 540 to number = 9999/540
remainder = 279
Required number = 9999 - 279 = 9720

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