The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?
  • 1869
  • 2859
  • 3571
  • 4427
Answer:- 1
Explanation:-

Solution:
LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571

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