A person has to completely put each of three liquids: 403 litres of petrol, 465 litres of diesel and 496 litres of Mobil Oil in bottles of equal size without mixing any of the above three types of liquids such that each bottle is completely filled. What is the least possible number of bottles required ?

134
244
346
4None of these

Answer:- 1

Explanation:-

Solution:

For the least number of bottles, the capacity of each bottle must be maximum.
Capacity of each bottle = HCF of 403 litres, 465 litres and 496 litres = 31 litres.
Hence,
required number of bottles

\begin{aligned} = (\frac{403 + 465 + 496}{31}) \\ = \frac{1364}{31} \\ = 44 \end{aligned}

$\eqalign{ & {\text{ = }}\left( {\frac{{403 + 465 + 496}}{{31}}} \right) \cr & = \frac{{1364}}{{31}} \cr & = 44 \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

For the least number of bottles, the capacity of each bottle must be maximum.
Capacity of each bottle = HCF of 403 litres, 465 litres and 496 litres = 31 litres.
Hence,
required number of bottles

\begin{aligned} = (\frac{403 + 465 + 496}{31}) \\ = \frac{1364}{31} \\ = 44 \end{aligned}

$\eqalign{ & {\text{ = }}\left( {\frac{{403 + 465 + 496}}{{31}}} \right) \cr & = \frac{{1364}}{{31}} \cr & = 44 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }