The least number of square tiles required to pave the ceiling of a room 15m 17cm long and 9m 2cm broad is = ?

1656
2738
3814
4902

Answer:- 1

Explanation:-

Solution:

For the least number of tiles, the size of the ltie must be the maximum.
Maximum size of the tile = HCF of 1517 cm and 902 cm = 41 cm.
Hence, required number of tiles

\begin{aligned} = \frac{Area of celling}{Area of each tile} \\ = (\frac{1517 \times 902}{41 \times 41}) \\ = 814 \end{aligned}

$\eqalign{ & {\text{ = }}\frac{{{\text{Area of celling}}}}{{{\text{Area of each tile}}}} \cr & = \left( {\frac{{1517 \times 902}}{{41 \times 41}}} \right) \cr & = 814 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

For the least number of tiles, the size of the ltie must be the maximum.
Maximum size of the tile = HCF of 1517 cm and 902 cm = 41 cm.
Hence, required number of tiles

\begin{aligned} = \frac{Area of celling}{Area of each tile} \\ = (\frac{1517 \times 902}{41 \times 41}) \\ = 814 \end{aligned}

$\eqalign{ & {\text{ = }}\frac{{{\text{Area of celling}}}}{{{\text{Area of each tile}}}} \cr & = \left( {\frac{{1517 \times 902}}{{41 \times 41}}} \right) \cr & = 814 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }