Let N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then sum of the digits in N is = ?
  • 14
  • 25
  • 36
  • 48
Answer:- 1
Explanation:-

Solution:
N = HCF of (4665 - 1305) (6905 - 4665) and (6905 - 1305)
= HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = (1 + 1 + 2 + 0) = 4

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