$HCF of \frac{2}{3}, \frac{4}{5} and \frac{6}{7} is = ?$ ${\text{HCF of }}\frac{2}{3}{\text{,}}\frac{4}{5}{\text{ and }}\frac{6}{7}{\text{ is = ?}}$

1⁴⁸/₁₀₅
2²/₁₀₅
3¹/₁₀₅
4²⁴/₁₀₅

Answer:- 1

Explanation:-

Solution:

\begin{aligned} HCF of fractional number is \\ = (\frac{HCF of numerator}{LCM of Denominator}) \\ ∴ HCF (\frac{2}{3}, \frac{4}{5}, \frac{6}{7}) \\ \Rightarrow (\frac{HCF of 2,4,6}{LCM of 3,5,7}) \\ \Rightarrow \frac{2}{3 \times 5 \times 7} \\ \Rightarrow \frac{2}{105} \end{aligned}

$\eqalign{ & {\text{HCF of fractional number is}} \cr & = \left( {\frac{{{\text{HCF of numerator}}}}{{{\text{LCM of Denominator}}}}} \right) \cr & \therefore {\text{HCF }}\left( {\frac{2}{3},\frac{4}{5},\frac{6}{7}} \right) \cr & \Rightarrow \left( {\frac{{{\text{HCF of 2,4,6}}}}{{{\text{LCM of 3,5,7}}}}} \right) \cr & \Rightarrow \frac{2}{{3 \times 5 \times 7}} \cr & \Rightarrow \frac{2}{{105}} \cr}$

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\begin{aligned} HCF of fractional number is \\ = (\frac{HCF of numerator}{LCM of Denominator}) \\ ∴ HCF (\frac{2}{3}, \frac{4}{5}, \frac{6}{7}) \\ \Rightarrow (\frac{HCF of 2,4,6}{LCM of 3,5,7}) \\ \Rightarrow \frac{2}{3 \times 5 \times 7} \\ \Rightarrow \frac{2}{105} \end{aligned}

\begin{aligned} HCF of fractional number is \\ = (\frac{HCF of numerator}{LCM of Denominator}) \\ ∴ HCF (\frac{2}{3}, \frac{4}{5}, \frac{6}{7}) \\ \Rightarrow (\frac{HCF of 2,4,6}{LCM of 3,5,7}) \\ \Rightarrow \frac{2}{3 \times 5 \times 7} \\ \Rightarrow \frac{2}{105} \end{aligned}

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$HCF of \frac{2}{3}, \frac{4}{5} and \frac{6}{7} is = ?$ ${\text{HCF of }}\frac{2}{3}{\text{,}}\frac{4}{5}{\text{ and }}\frac{6}{7}{\text{ is = ?}}$

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HCF of 23,45 and 67 is = ?HCF of 23,45 and 67 is = ?{\text{HCF of }}\frac{2}{3}{\text{,}}\frac{4}{5}{\text{ and }}\frac{6}{7}{\text{ is = ?}}

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$HCF of \frac{2}{3}, \frac{4}{5} and \frac{6}{7} is = ?$ ${\text{HCF of }}\frac{2}{3}{\text{,}}\frac{4}{5}{\text{ and }}\frac{6}{7}{\text{ is = ?}}$

NCERT
6 to 12